6x^2+20x=16

Solution for 6x^2+20x=16 equation:

6x^2+20x=16

We move all terms to the left:

6x^2+20x-(16)=0

a = 6; b = 20; c = -16;
Δ = b2-4ac
Δ = 202-4·6·(-16)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*6}=\frac{-48}{12}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*6}=\frac{8}{12}
=2/3
$